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Question

(B) Given equation: $x^{2}-3=\frac{2}{x}$Multiply both sides by $x$ (where $x 
eq 0$):$x(x^{2}-3) = 2$$x^{3}-3x = 2$Rearranging the terms to standard

Vedclass · Accepted Answer

No,it is not a quadratic equation.

Vedclass · Answer

(B) Given equation: $x^{2}-3=\frac{2}{x}$Multiply both sides by $x$ (where $x 
eq 0$):$x(x^{2}-3) = 2$$x^{3}-3x = 2$Rearranging the terms to standard form:$x^{3}-3x-2 = 0$Here,the highest power (degree) of the variable $x$ is $3$.$A$ quadratic equation must have a degree of $2$.Since the degree is $3$,the given equation is a cubic equation,not a quadratic equation.

Examine whether the following equation is quadratic or not: $x^{2}-3=\frac{2}{x}$

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